294m^2-24=0

Solution for 294m^2-24=0 equation:

294m^2-24=0

a = 294; b = 0; c = -24;
Δ = b2-4ac
Δ = 02-4·294·(-24)
Δ = 28224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{28224}=168$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-168}{2*294}=\frac{-168}{588}
=-2/7
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+168}{2*294}=\frac{168}{588}
=2/7
$